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#51 [–¼‘O‚È‚µ]
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(1)ƒ¿=4x¥y¥z^2(’¼ŒðÀ•WŒn)
0…ƒÏ…2A0…ƒÓ…ƒÎ/2A0…z…3(‰~“›À•WŒn)
(2)ƒ¿=[3ƒÎ(cosƒ¦)^2¥(cosƒÓ)^2]/[2¥r^2¥(r^2 +1)]
(‹…À•WŒn)
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:07/12/12 10:27
:P903i
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C-BoX E194.194