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#940 [„z —y ONEWayEXpress]
t^2
={(sinƒΖ/2)/(cosƒΖ/2)}^2
=(1-cosƒΖ)/(1+cosƒΖ)

cc

cosƒΖ=(1-t^2)/(1+t^2)

⏰:09/08/03 23:06 📱:SH903i 🆔:hMj8k/J.


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