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#260 [–Ό‘O‚Θ‚΅]
tanƒΖ=-1/γ5‚Μ‚Ζ‚«
sin(180ί-ƒΖ)=sinƒΖ=1/γ6
cos(180ί-ƒΖ)=-cosƒΖ=-γ5/γ6
tan(180ί-ƒΖ)=-tanƒΖ=1/γ5

⏰:09/01/22 23:19 📱:SH01A 🆔:™™™


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