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#260 [
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tanΖ=-1/γ5ΜΖ«
sin(180ί-Ζ)=sinΖ=1/γ6
cos(180ί-Ζ)=-cosΖ=-γ5/γ6
tan(180ί-Ζ)=-tanΖ=1/γ5
:09/01/22 23:19
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