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#185 [ΌOΘ΅]
(1)sin^2Ώ+cos^2Ώ+2sinΏcosΏ=1+sin2Ώ
(2)(cos^2Ώ+sin^2Ώ)(cos^2Ώ-sin^2Ώ)=1₯(1-sin^2Ώ-sin^2Ώ)=1-2sin^2Ώ=cos2Ώ
:09/09/13 21:51
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