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#185 [–Ό‘O‚Θ‚΅]
(1)sin^2ƒΏ+cos^2ƒΏ+2sinƒΏcosƒΏ=1+sin2ƒΏ

(2)(cos^2ƒΏ+sin^2ƒΏ)(cos^2ƒΏ-sin^2ƒΏ)=1₯(1-sin^2ƒΏ-sin^2ƒΏ)=1-2sin^2ƒΏ=cos2ƒΏ

⏰:09/09/13 21:51 📱:auωόTS3P 🆔:8s8sdW7c


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